![]() |
Home | Libraries | People | FAQ | More |
Return a reference to the underlying std::uint64_t
,
or throw an exception.
std::uint64_t& as_uint64();
If is_uint64()
is true
, returns a reference
to the underlying std::uint64_t
,
otherwise throws an exception.
Constant.
Strong guarantee.
Type |
Thrown On |
---|---|
|
|